Question

A car with mass 'M' is moving on horizontal road with velocity'V'. Driver applies accelerator and increases its speed 3 times to '3V'.The final K.E acquired by the car will be

Answer 1

Given :

Mass of the car = M

Initial velocity of the car = V

Final velocity of the car = 3V

To find :

The final kinetic energy of the car .

Solution :

Kinetic energy , K.E. = ( 1 / 2 ) * mass * velocity * velocity

Kinetic energy of the car = ( 1 / 2 ) * M * 3V * 3V

=> Kinetic energy of the car = ( 9 / 2 ) M$V^2$

The final kinetic energy of the car is ( 9 / 2 ) M$V^2$ .

Answer 2

Answer:

Step-by-step explanation:

answer is-:

4.5mv²