Question

A car with speed 60 km/he takes 8 hrs to travel some distance. What should be the increase in the speed if the same distance is to be covered in 7 integer 1/2

Answer 1

Question:

• A car with speed 60 km/hr takes 8 hrs to travel some distance. What should be the increase in the speed if the same distance is to be covered in $7\frac{1}{2}$ hours.

Answer:

$\large\bold\red{4\;\;Km{hr}^{-1}}$

Step-by-step explanation:

Let the distance to be covered be ‘x’ Km

$\bold \orange{ \underline{Case\;I}}$

• Speed, v = 60 Km/hr
• Time taken, t = 8 hr

We know that,

$\large \boxed { \bold \purple{Distance = Speed \times Time}}$

Therefore,

We get,

$= > x = vt \\ = > x = 60 \times 8 \\ = > x = 480 \: km$

Therefore,

Distance = 480 Km

Now,

$\bold \orange{ \underline{Case\;II}}$

Let the speed be ‘s’ km/hr

Also,

• Distance = 480 km
• Time taken =$7\frac{1}{2}$ hr

Therefore,

$= > s = \frac{480}{7 \frac{1}{2} } \\ \\ = > s = \frac{480}{ \frac{15}{2} } \\ \\ = > s = \frac{480 \times 2}{15} \\ \\ = >s = 64 \: \: km \: {hr}^{ - 1}$

Hence,

He should increase his speed by 4 km/hr

Answer 2

Given :----

• initial speed = 60km/h
• initial time = 8 hours .

To Find :----

• Speed of car increased if new time is 7(1/2) hours ?

Formula used :----

• Distance = Speed × Time
• Speed = Distance / Time

Solution :-----

car takes 8 hours at the rate of 60km/h to cover a distance ,

so, Total distance = S×T = 60×8 = 480km

Now, it has been said this same distance would be covered in 7(1/2) or 15/2 hours .

so,

Speed of car will be = D/T = 480 ÷ 15/2 = 480×2/15 = 64km/h .

inital speed = 60km/h .

so, increased in speed = 64 - 60 = 4km/h

Hence , speed of car will be 4km/h more to cover same distance in 7(1/2) hours .

(Hope it Helps you)