A car x starts at 5p.m. at a speed of 60 km/h. Another car y starts from the same point at 6:20p.m. at a speed of 80 Km/h .At what time will X and Y meet each other?
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EXPLANATION.
- GIVEN
A car x starts at 5 p.m at a speed of 60 km/hr
another car y starts from the same point at
6.20 p. m at a speed of 80 km/hr.
TO FIND TIME WILL X AND Y MEET
EACH OTHER.
According to the question,
when car y start from the place car x has
travelled = 1 hrs 20 min
Distance = Speed X Time.
Distance travelled by car x before car y
starts.
=> 60 X 4/3 = 80 km
Let car y meets car x after t hours.
Distance travelled by car y =
=> ( 80 X t) km
Distance travelled by car x from starting
time to the time it meets car y
=> ( 80 + 60 X t ) km
when both car meets
Distance travelled by both car
=> ( 80 X t) = ( 80 + 60 X t )
=> 80t = 80 + 60t
=> 20t = 80
=> t = 4
Therefore,
x and y meets each other = 4 hours.
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