A car X starts at 5pm at a speed of 60km/hr.Another car Y starts from the same point at 6:20pm at a speed of 80km/hr.At what time will X and Y meet each other?
Answers
Answer:
10 : 20 pm
Step-by-step explanation:
Hi,
Given that A car X starts at 5pm at a speed of 60km/hr.
Another car Y starts from the same point at 6:20 pm at a speed
of 80km/hr.
For the car X and Y to meet each other, both the cars should
have traveled the same distance,
Let the distance each travel be 'd'
If 't' is the time taken by X to travel d
Then time taken by Y will be t - 4/3 hr
Since, car Y travels 1 hr 20 minutes later
Speed of the car X , Vx = 60 kmph
Speed of the car Y, Vy = 80 kmph
Distance traveled by X = t*Vx
Distance traveled by Y = (t - 4/3)*Vy
But, t*Vx = (t - 4/3)*Vy
60t = 80(t - 4/3)
20t = 320/3
t = 16/3
= 5 Hr and 20 mins
Hence, So X and Y will meet after 5 Hr and 20 mins past 5 pm
= 10:20 pm
Hope, it helps !
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