A carbohydrates containing 40.0./. of C , 6.77./. of H and 53.3./. of O has a molecular mass of 180.2 u . determine its molecular formula.
Answers
Answer:
Answer:
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⚘Question:
An element forms an oxide A2O5 .
What will be the valency of the element A .
What will be the formula of chloride of the element.
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⚘Answers:
Valency of element of a chloride of A =5.
The formula for chloride of the element will be ACl5.
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⚘Solution:
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⚘Question1:
An element forms an oxide A2O5.
what will be the element of chloride A.
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⚘Answer:
Let us first define what is valency?
It is defined as the combining power of the element Specifically as measured by total number of hydrogen atoms it can easily displace or combine with.
Consider ,
The valency of element A be y,
Then,
2y+5 (-2)=0
Therefore, y=element of A=5.
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⚘Question2:
An element forms an oxide A2O5.
What will be the formula of chloride of the element .
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⚘Answer:
We know that,
The valency of an atom equals to the number of electrons in the outer shell.If that number may four or less than 4.
Since, here
Valency of element A is 5 and valency of chlorine is -1
Therefore, The formula of chloride of the element is (ACl 5) .
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Question:
> Carbohydrate containing 40% carbon, 6.73% hydrogen and 53.3% oxygen.
The molecular mass of compound is 180. Determine its molecular formula.
Answer:
∴ Empirical formula = CH2O.
Molecular mass of compound =180
Empirical mass = CH2O = 12 + 2 × 1.008 + 16 = 30 n = M.M/E.M = 180/30 = 6
Molecular formula = C6H12O6 = Glucose