Question

A carbon compound contains 12.8% carbon 2.1% hydrogen 85.1% bromine the molecular weight of the compound is 187.9 claculate molecular formula


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Answer 1

Answer:

Your answer is in the img from.

Answer 2

Answer:

Moles of C =

12

12.8

=1.067

Moles of H $=$\dfrac{2.1}{1.008}=2.08$$

Moles of Br =

79.9

85.1

=1.065

C=

1.065

1.067

=1, H=

1.065

2.08

=2, Br=

1.065

1.065

=1

Empirical formula =CH

2

Br

Molecular formula =(CH

2

Br)n

Empirical mass =93.9

Explanation:

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