A carbon compound contains 12.8% carbon 2.1% hydrogen 85.1% bromine the molecular weight of the compound is 187.9 claculate molecular formula
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Moles of C =
12
12.8
=1.067
Moles of H $=$\dfrac{2.1}{1.008}=2.08$$
Moles of Br =
79.9
85.1
=1.065
C=
1.065
1.067
=1, H=
1.065
2.08
=2, Br=
1.065
1.065
=1
Empirical formula =CH
2
Br
Molecular formula =(CH
2
Br)n
Empirical mass =93.9
Explanation:
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