A carbon compound X turns blue litmus to red and has a molecular formula C2H4O2. Identify X and draw it’s
structure. Write chemical equation for the reaction and name of the product formed in each case when X reacts with ethanol in the presence of conc.H2SO4 and sodium carbonate.
Answers
Answered by
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The compound is CH3COOH (Ethanoic Acid or Acetic Acid) X=CH3COOH
1. Reaction with Ethanol:(Esterification)
C2H5OH+CH3COOH -------> CH3COOC2H5 + H2O (IDK how to write conc. H2SO4 above the arrow.)
CH3COOC2H5 is Ethyl Ethanoate, a sweet smelling compound of functional group called Ester. (-COO-)
2. Sodium Bicarbonate
CH3COOH+Na2CO3------> CH3COONa + H2O
CH3COONa is Sodium Ethanoate.
1. Reaction with Ethanol:(Esterification)
C2H5OH+CH3COOH -------> CH3COOC2H5 + H2O (IDK how to write conc. H2SO4 above the arrow.)
CH3COOC2H5 is Ethyl Ethanoate, a sweet smelling compound of functional group called Ester. (-COO-)
2. Sodium Bicarbonate
CH3COOH+Na2CO3------> CH3COONa + H2O
CH3COONa is Sodium Ethanoate.
Answered by
1
X-Acetic Acid(CH3COOH)
CH3COOH+C2H5OH--------(conc. H2SO4)----->CH3-COO-CH2-CH3
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