Question

a carbon has highest fifth ionization potential value the no.of neutrons in its stable nuclide is​

Answer 1

Boron has 6 neutrons.

Explanation:

Given: A carbon has highest fifth ionization potential value.

Find: The no.of neutrons in its stable nuclide.

Solution:

E = 340eV

E = 13.6 z^2 / n^2​

For n = 1, 349 = 13.6 z^2 / 1^2

   z^2 = 3400 / 13.6

 z = root of 25 = 5

The element with atomic number 5 is Boron (B). Boron has 6 neutrons.