Physics, asked by rihanna50, 10 months ago

A carbon resistor of (54 ± 2.7) MW is to be marked with rings of different colours for its identification. The colour code sequence will be

Answers

Answered by zilmil123
12

Answer:

A carbon resistor of (54 ± 2.7) MW is to be marked with rings of different colours for its identification. The colour code sequence will be

Green – Yellow – Blue – Gold

Explanation:

Colour code of carbon resistor

Sol. : 54 MΩ = 54 × 106 Ω

Colour band : Green (5), Yellow (4), Blue (6)

Tolerance limit  =2.7/54x100=5%

Colour band for tolerance limit : Gold

So, sequence : Green – Yellow – Blue – Gold

Answered by Anonymous
3

Colour Number Multiplier

Black 0. 10^0

Brown 1. 10^1

Red. 2. 10^2

Orange 3. 10^3

Yellow 4. 10^4

Green. 5. 10^5

Blue. 6. 10^6

Violet. 7. 10^7

Grey 8. 10^8

White. 9. 10^9

tolerance

Gold. 5%. 10^-1

White. 10%.

Silver 20%. 10^-2

Gold

Silver

No Colour

trick to solve colour code problem

B B Roy Great Britain Very Good Wife wearing Gold Silver nackles

or

Black Brown Rods Of Your Gate Become Very Good When Given Silver Colour

taking concidration from above

Given

(54 + 2.7)MH

in ohm

(54*10^6 + 5%)

Colour attached to streep 5,2,6and tolerence 5% is

green ,yellow ,blue, and Gold

Similar questions