A card form a pack of 52 cards is lost. From the remaining cards of the pack, two cards are drawn at random and are found to be both clubs. Find the probability of the lost card being of clubs.
OR
From a lot of 10 bulbs, which includes 3 defectives, a sample of 2 bulbs is drawn at random. Find the probability distribution of the number of defective bulbs.
Answers
Answer:
D(0) = 42
D(1) = 21
D(2) = 6
Step-by-step explanation:
Total Bulbs = 10 ,
Defective = 3
OK bulb = 10 - 3 = 7
2 Bulbs are drawn
probability distribution of the number of defective bulbs.
D (2) means both bulbs are from Defective
so 2 bulbs from 3 Bulbs can be selected in 3 * 2 = 6 Ways
D(1) Means 1 Bulb from Defective & 1 Bulb from OK
= 3 * 7 = 21 Ways
D(0) Means all bulbs selected from 7 OK bulbs
= 7 * 6 = 42 Ways
D(0) = 42
D(1) = 21
D(2) = 6
Answer:
Step-by-step explanation:
Total Bulbs = 10 ,
Defective = 3
OK bulb = 10 - 3 = 7
2 Bulbs are drawn
probability distribution of the number of defective bulbs.
D (2) means both bulbs are from Defective
so 2 bulbs from 3 Bulbs can be selected in 3 * 2 = 6 Ways
D(1) Means 1 Bulb from Defective & 1 Bulb from OK
= 3 * 7 = 21 Ways
D(0) Means all bulbs selected from 7 OK bulbs
= 7 * 6 = 42 Ways
D(0) = 42
D(1) = 21
D(2) = 6