A card is drawn at random from a pack of 52 cards. Find the probability that the card
drawn is the ace of spades.
Answers
Answer:
queen
ANSWER
No. of cards in a pack =52
Solution(i):
No. of black kings =2
Therefore,
2
C
1
( Selecting 1 out of 2 items) times out of
52
C
1
( Selecting 1 out of 52 items) a black king is picked.
Let E be the event of getting a black king from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
2
C
1
=
52
2
=
26
1
Solution(ii):
No. of black cards or kings =28..... (26Black(including 2 Black kings) + 2 Red Kings)
Therefore,
28
C
1
( Selecting 1 out of 28 items) times out of
52
C
1
( Selecting 1 out of 52 items) a either a black card or a king is picked.
Let E be the event of getting either a black card or a king from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
28
C
1
=
52
28
=
13
7
Solution(iii):
No. of jack, queen or king =12 (4- Jack, 4- Queen, 4-King)
Therefore,
12
C
1
( Selecting 1 out of 12 items) times out of
52
C
1
( Selecting 1 out of 52 items) a jack, queen or a king is picked.
Let E be the event of getting a jack, queen or a king from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
12
C
1
=
52
12
=
13
3
Solution(iv):
No. of spade or ace =16 ........(13-Spade(including 1-Ace) + 3-Aces)
Therefore,
16
C
1
( Selecting 1 out of 16 items) times out of
52
C
1
( Selecting 1 out of 52 items) a spade or an ace is picked.
Let E be the event of getting a spade or an ace from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
16
C
1
=
52
16
=
13
4
Solution(v):
No. of neither ace nor king =52−8=44 ...... (As there are 4-Kings and 4-Aces)
Therefore,
44
C
1
( Selecting 1 out of 44 items) times out of
52
C
1
( Selecting 1 out of 52 items) a neither an ace nor a king is picked.
Let E be the event of getting neither an ace nor a king from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
44
C
1
=
52
44
=
13
11
Solution(vi):
No. of neither red nor queen $$=52-28=24$$ ...(26-red+ 2-Black Queen)
Therefore,
24
C
1
( Selecting 1 out of 24 items) times out of
52
C
1
( Selecting 1 out of 52 items) neither red nor a queen is picked.
Let E be the event of getting neither red nor queen from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
24
C
1
=
52
24
=
13
6
Solution(vii):
No. of non-ace cards =52−4= 48 ......(4 Aces)
Therefore,
48
C
1
( Selecting 1 out of 48 items) times out of
52
C
1
( Selecting 1 out of 52 items) non-ace card is picked.
Let E be the event of getting a non-ace card from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
48
C
1
=
52
48
=
13
12
Solution(viii):
No. of cards with no. 10 =4
Therefore,
4
C
1
( Selecting 1 out of 4 items) times out of
52
C
1
( Selecting 1 out of 52 items) card with no. 10 is picked.
Let E be the event of getting a card with no. 10 from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
4
C
1
=
52
4
=
13
1
Solution(ix):
No. of spade cards =13
Therefore,
13
C
1
( Selecting 1 out of 13 items) times out of
52
C
1
( Selecting 1 out of 52 items) a spade card is picked.
Let E be the event of getting a spade card from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
13
C
1
=
52
13
=
4
1
Solution(x):
No. of black cards =26
Therefore,
26
C
1
( Selecting 1 out of 26 items) times out of
52
C
1
( Selecting 1 out of 52 items) a black card is picked.
Let E be the event of getting a black card from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
52
C
1
26
C
1
=
52
26
=
2
1
Step-by-step explanation:
Multiple Shops!
(i) Variety of Products:
ADVERTISEMENTS:
Departmental stores offer variety of products to consumers; multiple shops sell only limited i.e. one or two lines of goods.
(ii) Location:
Departmental stores are centrally located and attract more customers, whereas multiple shops are scattered throughout the city and try to reach near to the customers.
(iii) Services:
ADVERTISEMENTS:
Departmental stores provide different type of services to their customers viz; free home delivery, after sales services, and recreational facilities etc. But multiple shops do not extend such services.
(iv) Basis of Sale:
Departmental stores sell both on cash and credit basis whereas multiple shops sell goods on cash basis only.
(v) Pricing:
ADVERTISEMENTS:
There is uniformity in charging prices by different branches of a multiple shop. But different departmental stores may charge different price for the same product.
(vi) Risk:
The departmental stores are confronted with greater business risks as they sell goods at one place or under one roof. The risks are considerably reduced on account of different branches of a multiple shop.
(vii) Advertising:
ADVERTISEMENTS:
The departmental stores advertise on local basis covering lesser area. On the other hand, multiple shops are widely scattered thereby covering large area.
(viii) Control and Co-Ordination:
Better managerial control and co-ordination can be ensured in the case of departmental stores as the staff work at one place. In case of multiple shops, it cannot be achieved properly as the workers employed in different branches at different places.
(ix) Operating expenses:
ADVERTISEMENTS:
Operating expenses of departmental stores are higher as compared to the multiple shops.
(x) Layout and design:
Departmental stores lay more emphasis on window dressing and internal decoration in order to attract the customers. Multiple shops on the other hand, have simple and uniform layout undertaken by all the branches of the shop.
(xi) Products of One or Of Different Manufacturers:
ADVERTISEMENTS:
Departmental stores sell product produced by different manufacturers. Multiple shops usually deal in the products of one manufacturer.
(xii) Adjustment of Losses:
In case of departmental stores, losses cannot be easily set off against the past profits. In case of multiple shops losses suffered by one branch can be easily set off against the profits earned by other branches.