Question

A card is drawn at random from a pack of 52 playing cards. Find the probability that the card drawn is either a king or an ace​

Answer 1

Answer:

if king 4/52 because there are 4 kings in a deck of cards

if ace the same goes like 4/52

Step-by-step explanation:

by using formula number of favourable outcomes/ total number of outcomes

Answer 2

Answer:

Total no. of outcomes = 52 {52 cards} (i) E⟶ event of getting a black king No of favourable outcomes = 2{king of spades & king of clubs} We know that, P(E) = (No. of favorable outcomes)/(Total no.of possible outcomes) = 2/52 = 1/26 (ii) E⟶ event of getting either a black card or a king. No. of favourable outcomes = 26 + 2 {13 spades, 13 clubs, king of hearts & diamonds} P(E) = (26+2)/52 = 28/52 = 7/13 (iii) E⟶ event of getting black & a king. No. of favourable outcomes = 2 {king of spades & clubs} P(E) = 2/52 = 1/26 (iv) E⟶ event of getting a jack, queen or a king No. of favourable outcomes = 4 + 4 + 4 = 12 {4 jacks, 4 queens & 4 kings} P(E) = 12/52=3/13 (v) E⟶ event of getting neither a heart nor a king. No. of favourable outcomes = 52 – 13 – 3 = 36 {since we have 13 hearts, 3 kings each of spades, clubs & diamonds} P(E) = 36/52 = 9/13 (vi) E⟶ event of getting spade or an all. No. of favourable outcomes = 13 + 3 = 16 {13 spades & 3 aces each of hearts, diamonds & clubs} P(E) = 16/52 = 4/13 (vii) E⟶ event of getting neither an ace nor a king. No. of favourable outcomes = 52 – 4 – 4 = 44 {Since we have 4 aces & 4 kings} P(E) = 44/52 = 11/13 (viii) E⟶ event of getting neither a red card nor a queen. No. of favourable outcomes = 52 – 26 – 2 = 24 {Since we have 26 red cards of hearts & diamonds & 2 queens each of heart & diamond} P(E) = 24/52 = 6/13 (ix) E⟶ event of getting card other than an ace. No. of favourable outcomes = 52 – 4 = 48 {Since we have 4 ace cards} P(E) = 48/52 = 12/13 (x) E⟶ event of getting a ten. No. of favourable outcomes = 4 {10 of spades, clubs, diamonds & hearts} P(E) = 4/52=1/13 (xi) E⟶ event of getting a spade. No. of favourable outcomes = 13 {13 spades} P(E) = 13/52 = 1/24 (xii) E⟶ event of getting a black card. No. of favourable outcomes = 26 {13 cards of spades & 13 cards of clubs} P(E) = 26/52=1/2 (xiii) E⟶ event of getting 7 of clubs. No. of favourable outcomes = 1 {7 of clubs} P(E) = 1/52 (xiv) E⟶ event of getting a jack. No. of favourable outcomes = 4 {4 jack cards} P(E) = 4/52=1/13 (xv) E⟶ event of getting the ace of spades. No. of favourable outcomes = 1{ace of spades} P(E) = 1/52 (xvi) E⟶ event of getting a queen. No. of favourable outcomes = 4 {4 queens} P(E) = 4/52 = 1/13 (xvii) E⟶ event of getting a heart. No. of favourable outcomes = 13 {13 hearts} P(E) = 13/52 = 1/4 (xviii) E⟶ event of getting a red card. No. of favourable outcomes = 26 {13 hearts, 13 diamonds} P(E) = 26/52 = 1/2Read more on Sarthaks.com - https://www.sarthaks.com/102109/a-card-is-drawn-at-random-from-a-pack-of-52-cards-find-the-probability-that-card-drawn-is