Question

A Card is drawn at random from a pack
of well Shuffled 52 playing Cards find
the probability that the card drawn is
e A king Card abd Red Coloured card.​

Answer 1

Given:

A card is drawn at random from a pack of 52 well-shuffled playing cards.

To find:

The probability of getting

(i) A king Card and Red Coloured card.​

So,

There are four different cards,

Clubs (black) = 13. Here 1 to 10 and 1 king, 1 queen, and 1 jack

Spades (black) = 13. Here 1 to 10 and 1 king, 1 queen, and 1 jack

Diamond (red) = 13. Here 1 to 10 and 1 king, 1 queen, and 1 jack

Heart (red) = 13. Here 1 to 10 and 1 king, 1 queen, and 1 jack

So,

A king card = 4

Red colour cards = 13 - 2(king cards, as 2 red king cards are mentioned above) = 11

So,

A king and red colour card = 4 + 11 = 15

Therefore,

Number of favourable outcomes = 15

Total number of possible outcomes = 52

Hence,

$Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

So,

Probability of getting a king card and a red coloured card is

$= \frac{15}{52}$

Answer 2

Answer:

Given :-

A card is drawn at random from a pack of 52 well-shuffled playing cards.

To Find :-

• Probability of coming King and Red card

Solution :-

As we know that there are 4 types of cards

$\sf\clubs \: = 1 \: to \: 10 \: \: \: \: 1 \: king \: 1 \: \: queen \: \: 1 \: jack$

$\sf\spades \: = 1 \: to \: 10 \: \: \: \: 1 \: king \: 1 \: \: queen \: \: 1 \: jack$

$\sf \red \hearts\: = 1 \: to \: 10 \: \: \: \: 1 \: king \: 1 \: \: queen \: \: 1 \: jack$

$\sf\red \diamond \: = 1 \: to \: 10 \: \: \: \: 1 \: king \: 1 \: \: queen \: \: 1 \: jack$

Total king = 1 + 1 + 1 + 1 = 4

Total red cards = (13 + 13) - 2 = 24

Now,

P(E) = Favourable Outcome/Total Outcomes

P(E) = (24 + 4)/52

P(E) = 28/52

P(E) = 7/13