Question

A card is drawn at random from a well shuffled pack of 52 cards. find the probability of getting neither 7 or 9 of club​

Answer 1

Answer:

there are 52 cards in pack

thus n(S)=52

let event A be E(A) that is of club of 7

thus n(A) = 1

thus P(A) = n(A) / n(S)

= 1/25

similarly, event B will be club of 9 and as n(B) is also 1 thus P(A) = 1/25

Step-by-step explanation:

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