A card is drawn at random from a well shuffled pack of 52 playing cards.find the probability of getting
neither a red card nor a queen
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Hi there !
Here's the answer:
Let S be Sample space
n(S) = no. of ways of a card from 52 Cards= 52C1= 52
E be the Event of getting neither red nor queen.
n(E) = No. of ways of getting neither red nor queen
No. of red cards = 26
No. of queen cards = 4
Common cards = 2 (Red queens)
Total no. of cards that are EITHER red OR queen = 26 + 4 -2 = 28.
Total no. of cards that are NEITHER red NOR queen = {TOTAL CARDS(52)} - {No. of cards that are EITHER red OR queen}
= 52 - 28 = 24
This is nothing but n(E) .
=> n(E)= 24.
Required Probability = n(E) / n(S)
= 24 / 52 = 6 / 13
•°• Required Probability = 6 / 13
:)
hope it helps
comment if you need to know anything
Here's the answer:
Let S be Sample space
n(S) = no. of ways of a card from 52 Cards= 52C1= 52
E be the Event of getting neither red nor queen.
n(E) = No. of ways of getting neither red nor queen
No. of red cards = 26
No. of queen cards = 4
Common cards = 2 (Red queens)
Total no. of cards that are EITHER red OR queen = 26 + 4 -2 = 28.
Total no. of cards that are NEITHER red NOR queen = {TOTAL CARDS(52)} - {No. of cards that are EITHER red OR queen}
= 52 - 28 = 24
This is nothing but n(E) .
=> n(E)= 24.
Required Probability = n(E) / n(S)
= 24 / 52 = 6 / 13
•°• Required Probability = 6 / 13
:)
hope it helps
comment if you need to know anything
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