A card is drawn at random from a well-shuffled pack of cards numbered 1 to 20. Find the probability of (i) getting a number less than 7 (ii) getting a number divisible by 3
Answers
( {7}^{ - 1} - {8}^{ - 1} )^{ - 1}
Given,
Cards are numbered from 1 to 20.
To find,
The probability of (i) getting a number less than 7 (ii) getting a number divisible by 3.
Solution,
The probability of (i) getting a number less than 7 will be 3/10 and (ii) getting a number divisible by 3 will be 3/10.
We can easily solve this problem by following the given steps.
According to the question,
Cards are numbered from 1 to 20.
We know that the formula to find the probability of an event is given as follows:
Probability = Number of favourable outcomes/total number of outcomes
(i) Numbers less than 7 = 1,2,3,4,5,6
Total number of outcomes = 20
Probability of getting a number less than 7 = 6/20
Probability of getting a number less than 7 = 3/10
(ii) Numbers divisible by 3 = 3,6,9,12,15,18
Probability of getting a number divisible by 3 = 6/20
Probability of getting a number divisible by 3 = 3/10
Hence, the probability of (i) getting a number less than 7 is 3/10 and (ii) getting a number divisible by 3 is 3/10.