Question

A card is drawn from a pack of cards, find the probability that neither
it is an ace nor a King.​

Answer 1

Answer:

2/52= 1/26

Step-by-step explanation:

is the right answer

Answer 2

${\huge{\boxed{\underline{\textsf{\textbf{\color{pink}{Final\:An}{\pink{sw}{\purple{er:-}}}}}}}}}$

$\fbox{\frac{11}{13}}$$\boxed{\frac{11}{13}}$

$\huge\underbrace\red{\dag Given:- \dag}$

A card is drawn from a pack of cards

$\huge\underbrace\pink {\dag To Find:- \dag}$

To find the probability that card is neither an ace nor a King

$\huge\underbrace\green {\dag Formula\:Used:- \dag}$

$Probability = \frac{number \ of \ favorable \ outcomes} {total \ number\ of \ outcomes}$

$\huge\underbrace\green {\dag some \ things \ to \ know :-\dag}$

• In set of 52 playing cards . 13 of each suit: clubs, diamonds, hearts, and spades

• Each set (13 card) have:- $Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King$

$\huge\underbrace\purple{\dag Solution:- \dag}$

Here in deck of card there are total 4 kings and 4 aces total 8 cards

Therefore cards remaining in set $=52-8 \implies 44 \ cards$

Probability of getting a card that neither

it is an ace nor a King $= \frac{number \ of \ favorable \ outcomes} {total \ number\ of \ outcomes}$  

$=\frac{44}{52}$

$=\frac{11}{13}$

Hence probability of getting a card that is neither ace nor king is $\farc{11}{13}$

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