Question

A card is drawn from a well shuffled pack of 52. Find the probability that the card drawn is a card of spade or an ace

Answer 1

13/15 and 13/15 is the answer

Answer 2

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S = { 1, 2, 3, 4, 5, 6, 7, ...................52}

n(S) = 52

We know that, there are

13- spade card

13- club card

13-heart card

13- diamond card

4- Ace

Let event A : That the card drawn is a card of spade .

A = { 13}

n(A) = 13

Probability of event A,

$P(A) = \frac{n(A)}{n(S)} \\ \\ P(A) = \frac{13}{52}$

$P(A) = 4$

Let event B : That the card drawn is an Ace

B = { 4}

n(B) = 4

Now, probability of event B

P(B) = n(B)/n(S)

P(B) = 4/52

P(B) = 1/13

Thanks