Question

A card is drawn from a well shuffled playing of Pak card what is the probability that getting a red card and find the probability of a card is not ace

Answer 1

Step-by-step explanation:

$\blue{\mathfrak{\large{Total \: number \: of \: cards=52}}} \\ \blue{\mathfrak{\large{Number \: of \: red \: cards(heart+diamond \: cards)}}} \\ \blue{\mathfrak{\large{=13+13}}} \\\blue{\mathfrak{\large{=26}}}\\ \blue{\mathfrak{\large{Number \: of \: ace \: cards =4}}} \\ \blue{\mathfrak{\large{Number \: of \: not \: ace \: cards }}} \\ \blue{\mathfrak{\large{=52-4}}}\\ \blue{\mathfrak{\large{=48}}} \\ \red{\mathfrak{\large{probability \: of \: getting \:red \: card }}} \\ \blue{\mathfrak{\large{= \frac{Number \: of \: red \: cards(heart+diamond \: cards)}{Total \: number \: of \: cards} }}} \\ \blue{\mathfrak{\large{= \frac{26}{52} }}} \\ \blue{\mathfrak{\large{= \frac{1}{2} }}} \\ \red{\mathfrak{\large{probability \: of \: getting \: not \: ace \: card}}} \\ \blue{\mathfrak{\large{ = \frac{Number \: of \: ace \: cards}{Total \: number \: of \: cards} }}} \\ \blue{\mathfrak{\large{= \frac{48}{52} }}} \\ \blue{\mathfrak{\large{ = \frac{12}{13} }}} \\ \\ \green{\mathfrak{\underline{\large{Hope \: It \: Helps \: You}}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$