Question

A card is drawn from each of two well-shuffled packs of cards the probability that at least one of them is an ace

Answer 1

Answer:

Probability will be = 1 - no ace

$1 - \frac{48}{52} \times \frac{48}{52} = \frac{169 - 144}{169} = \frac{25}{169}$

Answer 2

The probability that at least one of them is an ace is $\frac{25}{169}$

Step-by-step explanation:

total ace in the well-shuffled packs of cards = 4

since , there are 2 pack of cards

therefore

let we first find the probability of no aces in two pack of cards = $\frac{48}{52}\times \frac{48}{52}$

probability of atleast one ace

= 1 - (probability of no aces )

=$1- (\frac{48}{52}\times \frac{48}{52})\\\\1- (\frac{12}{13}\times \frac{12}{13})\\\\1- \frac{144}{169}\\\\\frac{25}{169}$

hence , The probability that at least one of them is an ace is $\frac{25}{169}$

#Learn more :

One card is drawn from a well shuffled pack of 52 cards. The probability of getting an ace is

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