Question

A card is drown at random from
a well shuffled pack of 52 cards
and card drawn is red and it is
Kept aside. Now from the remaining
51 cards a
card is drawn at
random.write probability of getting
1)a black card
card
)2a red card​

Answer 1

Step-by-step explanation:

The probability of a random card being red is 1/2 since half the cards are red and half are black.

The probability of a random card being red is 1/2 since half the cards are red and half are black.The probability that a random card is a king is 1/13 since there are thirteen cards in each suite.

The probability of a random card being red is 1/2 since half the cards are red and half are black.The probability that a random card is a king is 1/13 since there are thirteen cards in each suite.You can calculate the probability of a card being red or a king in (at least) two different ways:

The probability of a random card being red is 1/2 since half the cards are red and half are black.The probability that a random card is a king is 1/13 since there are thirteen cards in each suite.You can calculate the probability of a card being red or a king in (at least) two different ways:(number of red cards + number of black kings) / total number of cards, or (26+2)/52≈53.8% .

The probability of a random card being red is 1/2 since half the cards are red and half are black.The probability that a random card is a king is 1/13 since there are thirteen cards in each suite.You can calculate the probability of a card being red or a king in (at least) two different ways:(number of red cards + number of black kings) / total number of cards, or (26+2)/52≈53.8% .Probability of red card + probability of king - probability of red king, or Pr+Pk−Pr×Pk=12+113−126≈53.8%

The probability of a random card being red is 1/2 since half the cards are red and half are black.The probability that a random card is a king is 1/13 since there are thirteen cards in each suite.You can calculate the probability of a card being red or a king in (at least) two different ways:(number of red cards + number of black kings) / total number of cards, or (26+2)/52≈53.8% .Probability of red card + probability of king - probability of red king, or Pr+Pk−Pr×Pk=12+113−126≈53.8% Of course, if you mean the likelihood of a card being red or a king, but NOT both red and a king, it’s 1/2 since you just replace two red kings with two black kings.