a card is picked at random from a pack of 20 cards numbered 1,2,3,4......20. Find the probability that the card is even or the card is multiple of 4?
Answers
Answered by
1
Answer:
P=1/2
Step-by-step explanation:
n(s)=20
since, the card is to be a multiple of four or even
so, p={2,4,6,8,10,12,14,16,18,20}
n(p)=10
p(of getting card which is even or multiple of four)=n(p)/n(s)
=10/20=1/2
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muhammadarslan2:
brainliest
Answered by
1
Answer:
Step-by-step explanation:
Among the 20 cards
Even cards are 2,4,6,8,10,12,14,16,18,20
Probability of getting an even card : 10/20 [ P(A) ]
Multiples of 4 : 4,8,12,16,20
Probability of getting a multiple of 4: 5/20 [ P(B) ]
Probability of card is even and multiple of 4 [ie. P(A n B) ] = 5/20
Probability if card is even or multiple of 4 [ ie. P( A u B ] = 10/20+5/20-5/20
=>10/20
=> 1/2
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