A card is selected at random from a pack of 52 playing cards. Consider the events A = {diamond}, B = {face card}. If P(A) = x/y where x and y are co-prime integers, then find x + y.
Answers
Answered by
3
Step-by-step explanation:
Let E
1
= Event that lost card is a spade.
E
2
= Event that lost card is a non-spade.
A= Event that three spades are drawn without replacement from 51 cards.
P(E
1
)=
52
13
=
4
1
P(E
2
)==1−
4
1
=
4
3
P(
E
1
A
)=
51
C
3
12
C
3
,P(
E
2
A
)=
51
C
3
13
C
3
P(
A
E
1
)=
4
1
.
51
C
3
12
C
3
+
4
3
.
51
C
3
13
C
3
4
1
.
51
C
3
12
C
3
=
49
10
hope it helps you
Answered by
0
Answer:
The answer is 5 .
Step-by-step explanation:
Given :- 52 cards
- A= { diamond } , B = { face card }
- P(A) =
.
To find :- value of
Solution :-
Step 1)
- In deck of 52 cards , we have
- 13 cards of diamond
- 12 face cards .
Step 2) Hence , probability of A = { diamond } is ,
P(A) = 13 / 52 = 1/4 = x/y
Thus , x = 1 , y = 4
Step 3) Value of x + y = 1+4 = 5 .
Hence, the answer is 5 .
#SPJ3
Similar questions