A card is selected between 10 and 60. Find the probability of (i) number divisible by 10, (ii) perfect cube,(iii) prime number greater than 45
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total no of outcome is 49
I)no divisible by 10 is 20, 30,40,50
probability of getting a bit divisible by 10 is 4/4
2) perfect cube no between 10 to 60 is 27
probability of getting a cube no is 1/49
3) prime no greater than 45 are 47, 53 and 59
probability is 3/49
I)no divisible by 10 is 20, 30,40,50
probability of getting a bit divisible by 10 is 4/4
2) perfect cube no between 10 to 60 is 27
probability of getting a cube no is 1/49
3) prime no greater than 45 are 47, 53 and 59
probability is 3/49
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Answer:
Step-by-step explanation:
Total number of outcomes=61
Outcomes in which number is divisible by 10 = {10,20,30,40,50,60}
Number of favourable of outcomes=6
P(getting a number divisible by 10)=6/61
Outcomes in which number is perfect cube= {27}
Number of favourable outcomes=1
P(getting a perfect cube)=1/61
Outcomes in which number is prime no. greater than 45={47, 53, 59}
Number of favourable outcomes=3
P(getting prime number>45)=3/61
moulika75:
between 10 to 60 so we must not include 10 and 60
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