Question

a cardboard box is 1. 4 CM long 75 cm wide and 49 CM height how many bars of soaps can be put into it if each bar measure 6 Cm x 5 cm x 3.5 cm​

Answer 1

Answer:

$† {\underline{\boxed{\frak{\pink{~Answer ~In ~ Short}}}}}† \:$

l= 1.4

b= 75

h=49

tsa = 2(lb+bh+hl)

= 2( 1.4×75 + 75×49 + 49×1.4)

= 2× 105 + 3675 + 68.6)

= 25,2315 cm²

Answer 2

Question -

A cardboard box is 1.4cm long 75 cm wide and 49cm height. How many bars of soaps can be put into it if each bar measure 6 cm x 5 cm x 3.5 cm?

Given -

• Length of the box = 1.4 cm
• Breadth of the box = 75 cm
• Height of the box = 49 cm
• Length of the soap bar = 6 cm
• Breadth of the soap bar = 5 cm
• Height of the soap bar = 3.5 cm

To find -

• No. of soap bars that can be put into the box.

Solution -

$\sf \: Volume \: of \: the \: box = l × b × h \\ \sf \: =( 1.4 \times 75 \times 49) {cm}^{3} \\ \sf \: = 5145 \: {cm}^{3}$

$\sf \: Volume \: of \: the \: soap \: bar = l × b × h \\ \sf \: = (6 \times 5 \times 3.5) {cm}^{3} \\ \sf \: = 105 \: {cm}^{3}$

$\sf \therefore \: No. of \: soap \: bar = \dfrac{ Volume \: of \: the \: box}{Volume \: of \: the \: soap \: bar } \\ \\ \sf \: = \frac{ \cancel{5145} \: ^{49} }{ \cancel{105}} \\ \\ \boxed{ \red{ \bold{ \: = 49 \: soap \: bar.. }}}$