Question

A care arolerates walkerumleg
from 18 km/h to 36 km/h ch Ss
Find & the acceleration
(1) distance covered by the most
that time​

Answer 1

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

u=18×100060×60s

u = 5 m/s

Final velocity (v) =36km/hour

v=36×100060×60s

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m