A care travelling at 54kmh-1 slows down uniformly to a velocity of 18kmh-1 when the brakes were applied: how Long does it cover a distance of 50m?then what is the deceleration?
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Answered by
8
Convert:-
Initial Velocity,
=> 54 Kmh^-1 to ms^-1
=> (54 x 5/18) ms^-1 = 15 m/s
Again,
Final Velocity,
=> 18 Kmh^-1 to ms^-1
=> (18 x 5/18) m/s = 5 m/s
Distance = S = 50 m
Now, We are required to find out Acceleration.
=> v^2 = u^2 + 2aS
=> (5)^2 = (15)^2 + 2 x a x 50
=> 25 = 225 + 100 a
=> 25-225 = 100 a
=> -200 = 100a
=> -(200/100) = a
=> a = -2 ms^-2
Be Brainly
Initial Velocity,
=> 54 Kmh^-1 to ms^-1
=> (54 x 5/18) ms^-1 = 15 m/s
Again,
Final Velocity,
=> 18 Kmh^-1 to ms^-1
=> (18 x 5/18) m/s = 5 m/s
Distance = S = 50 m
Now, We are required to find out Acceleration.
=> v^2 = u^2 + 2aS
=> (5)^2 = (15)^2 + 2 x a x 50
=> 25 = 225 + 100 a
=> 25-225 = 100 a
=> -200 = 100a
=> -(200/100) = a
=> a = -2 ms^-2
Be Brainly
Answered by
0
Explanation:
what is the retardation
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