Question

A care travelling at 54kmh-1 slows down uniformly to a velocity of 18kmh-1 when the brakes were applied: how Long does it cover a distance of 50m?then what is the deceleration?

Answer 1

Convert:-
Initial Velocity,

=> 54 Kmh^-1 to ms^-1

=> (54 x 5/18) ms^-1 = 15 m/s

Again,

Final Velocity,

=> 18 Kmh^-1 to ms^-1

=> (18 x 5/18) m/s = 5 m/s

Distance = S = 50 m

Now, We are required to find out Acceleration.


=> v^2 = u^2 + 2aS

=> (5)^2 = (15)^2 + 2 x a x 50

=> 25 = 225 + 100 a

=> 25-225 = 100 a

=> -200 = 100a

=> -(200/100) = a

=> a = -2 ms^-2




Be Brainly

Answer 2

Explanation:

what is the retardation