A carnival manager counted 275 ticket receipts after the first day of the carnival. The price for an adult ticket was $11.50, and the price for a student ticket was $10. The total amount of money collected was $2,930.
Answers
Answer:
Step-by-step explanation:
let the no. of adult tickets be x
let the no. of student ticket be y
APQ,x+y=275
x=275-y...............................(equation 1)
Also,11.5x+10y=2930........(multiply by 10)
115x+100y=29300.............(equation 2)
Sub 1 in 2
115(275-y)+100y =29300
31,625 -115y +100y =29300
31,625 -15y =29300
15y = 31625-29300
15y=2325
y=155
sub y in equation 1
x=275-155
x=120
so the no. of student tickets =155
adult tickets =120
Hope this helps you!
Given : A carnival manager counted 275 ticket . price for an adult ticket was $11.5, and student ticket was $10. Total Amount = $ 2930
To find : system of equations represents the situation and Adults & students tickets sold
Solution:
number of adult tickets = x
number of student tickets = y
carnival manager counted 275 ticket
=> x + y = 275 Eq1
The price for an adult ticket was $11.5
price for a student ticket was $10
Total Amount = 11.5x + 10y
total amount of money collected was $2,930.
=> 11.5x + 10y = 2930 Eq2
system of equations represents the situation :
x + y = 275
11.5x + 10y = 2930
Eq2 - 10 * Eq1
=> 11.5x - 10x = 2930 - 2750
=> 1.5x = 180
=> x = 120
120 + y = 275
=> y = 155
120 Adults & 155 Student tickets
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