A carnot cycle has an efficiency of 40% its low temperature reservoir is at 7 degree Celsius what is the temperature of source
Answers
Answered by
14
For a Carnot engine,
Eff = 1 - Tc/Th
where
Tc = cold reservoir temperature
Th = hot reservoir temperature
For an efficiency of 40%, then
0.40 = 1 - (7 + 273)/Th
NOTE - temperature must be converted to the absolute Kelvin scale
0.40 = 1 - 280/Th
0.60Th = 280
Th = 466.66 K = 466.66 - 273
Th = 193.66 C
Eff = 1 - Tc/Th
where
Tc = cold reservoir temperature
Th = hot reservoir temperature
For an efficiency of 40%, then
0.40 = 1 - (7 + 273)/Th
NOTE - temperature must be converted to the absolute Kelvin scale
0.40 = 1 - 280/Th
0.60Th = 280
Th = 466.66 K = 466.66 - 273
Th = 193.66 C
Similar questions