Question

A carnot cycle is performed by air initially at 327 c each stage represent compression or expansion are in ratio 1:6 what is lowest temperature

Answer 1

Explanation:

Given A carnot cycle is performed by air initially at 327 c each stage represent compression or expansion are in ratio 1:6 what is lowest temperature and efficiency of the cycle.

• We know that TV^ ˠ - 1 = constant
• So T 1 = 327 + 273 = 600 K
• V1 = 1, V2 = 6, T2 = ?
• So we get
• 600 x 1 ^1.4 – 1 = T2 x 6^1.4 – 1
• So T2 = 600 x 1^1.4 – 1 / 6^1.4 – 1
•           = 292.6 K
•          = 292.6 – 273
•         = 19.7 degree Celsius
• Now the minimum temperature is 19 degree Celsius.
• So the Efficiency is given by
• T1 – T2 / T1
• = 600 – 292.6 / 600
• = 0.512
• = 51.3%

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Answer 2

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