Question

a Carnot cycle is working with source temperature 227°c and sink temperature 127°C keeping the sink temperature same.find the temperature of the source to be changed to double the efficiency​

Answer 1

Answer:

Let, temp. of Source T1= 227+273=500K

      temp of  Sink      T2= 127+273=400K

    efficiency n1=(1-T2/T1) =(1-400/500) = 0.2

When Efficiency is Doubled n2=2*n1 =2*0.2=0.4

now, 0.4=1-400/T

    or, 400/T=0.6

          T=400/0.6=666.67K

Therefore, The temperature of the source to be changed to double the efficiency​ = (666.67-500)K=167.67K

Answer 2

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