Question

A carnot engine A operates between TK and 540K.Another carnots engine B operates between 200K and 600k. Find temperature T if both engines have same efficiency

Answer 1

Answer:540/T = 600/200

540/T = 3

3T = 540

T=180K

Explanation:

n=1-T2/T1

Answer 2

The temperature of engine A is 180 K.

Explanation:

Given that,

Initial temperature for engine A = 540 K

Initial temperature for engine B = 200 K

Final temperature for engine B = 600 K

If both engines have same efficiency

We need to calculate the temperature of engine A

Using formula of efficiency

$\eta_{1}=\eta_{2}$

$1-\dfrac{T_{1}}{T_{2}}=1-\dfrac{T_{1}}{T_{2}}$

Put the value into the formula

$1-\dfrac{T}{540}=1-\dfrac{200}{600}$

$\dfrac{T_{1}}{540}=1-\dfrac{200}{600}-1$

$T_{1}=\dfrac{200}{600}\times540$

$T_{1}=180\ K$

Hence, The temperature of engine A is 180 K.

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Topic : efficiency

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