Question

A carnot engine has the same efficiency between 800 K to 500k and xk to 600K the value of 'r' is​

Answer 1

Answer:

Efficiency of a carnot's engine

η = 1 – Tc/Th

Same efficiency implies

Tc1/Th1 = Tc2/Th2

500/800 = 600/T

T = 960k

THANK YOU

Answer 2

Answer:

960K

Explanation:

n1=( T1- T2) /T1

n1=(1-500)/800=3/8

n2=(1-600)/x

(x-600)/x=3/8

(600*8)/5=960k