Question

A carnot engine is working between sink temperature 27 c and source temperature 227
c. Calculate the efficiency of the carnot engine.

Answer 1

Answer:

40%

Explanation:

efficiency of carnot engine is given by

n=1 -(T1/T2)

where T1 and T2 are in kelvin.

Answer 2

The efficiency of the carnot engine is 40 percent.

Explanation:

Given that,

Temperature of sink, $T_2=27^{\circ}=27+273=300\ K$

Temperature of the source, $T_1=227\ C=227+273=500\ K$

The efficiency of the carnot engine is given by formula as follows :

$\eta=1-\dfrac{T_2}{T_1}\times 100\\\\\eta=(1-\dfrac{300}{500})\times 100\\\\\eta=40\%$

So, the efficiency of the carnot engine is 40 percent. Hence, this is the required solution.

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