Question

A Carnot engine operates between 500K and 400K. If it absorbs 3x105 cal heat at higher temperature, how much work per cycle can the engine perform?

Answer 1

Answer: The work done by the Carnot engine is $W = 252\ kJ$

Explanation:

Given that,

Temperature $T_{c} = 400K$

Temperature $T_{h} = 500K$

Absorbs heat $Q = 3\times10^{5}\ cal$

We know that,

The work done by the Carnot engine

$W = Q(1-\dfrac{T_{c}}{T_{h}})$

$W = 3\times4.2\times10^{5}\ J(1-\dfrac{400}{500})$

$W = 2.52\times10^{5}\ J$

$W = 252\ kJ$

Hence, The work done by the Carnot engine is $W = 252\ kJ$.