A carnot engine operates with source at 127°c and sink at 27°c . I f the source supplied 40 kj of heat energy then the work done by the engine is
Answers
Answered by
10
source temperature = 127°=127+273=400k
sink temperature=27°c=27+273=300k
efficiency=1-T2÷T1
=1-400÷300
=1÷4
workdone=1÷4×40=10j
Answered by
0
Answer:
Explanation:
source temperature = 127°=127+273=400k
sink temperature=27°c=27+273=300k
efficiency=1-T2÷T1
=1-400÷300
=1÷4
workdone=1÷4×40=10j
Similar questions