Question

a carnot engine operating between temperature T1=400k and T2=300k absorbs 100 calories of heat from the source. which of the following is correct?​

Answer 1

Explanation:

a carnot engine operating between temperature T1=400k _T2 =300 =100

Answer 2

Given:

• A carnot engine operating between temperatures T1: 400k and T2: 300k.
• The engine absorbs calories of heat from the source is 100.

Both temperatures are divided into two parts where temperature T1 is applied to the source and temperature T2 is applied to the sinX.

The temperature of the source always stays greater than the temperature of sinX.

                                        T2<T1

By the formula of heat efficiency,

                                                          η = 1 - T2/T1

                                                          η = 1 - 300/400

                                                          η = 1 - 0.75

                                                         η = 0.25