A Carnot engine operating between temperatures T1 and T2 has efficiency 1/6. When T2 is lowered by 62K its efficiency increases to 1/3.Then T1 and T2 are , respectively
1)330K and 268K 2)310K and 248K 3)372K and 310K 4)372K and 330K
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Answer:
Hey mate your answer is here
That is T1= 372
T2=310
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Answered by
1
Given that,
Efficiency
We need to calculate the value of T₂
Using formula of the efficiency of carnot engine
Put the value into the formula
...(I)
When T₂ is lowered by 62K its efficiency increases to 1/3.
We need to calculate the value of T₁
Using formula of efficiency
Put the value into the formula
Put the value of T₂
Now, Put the value of T₁ in equation (I)
Hence, The value of T₁ and T₂ is 372 K and 310 K.
(3) is correct option
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Topic : efficiency
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