Physics, asked by iamdeepak482, 1 year ago

a carnot engine operating between temperatures t1 and t2 has efficency 1/6.when t2 is lowered by 62k its efficency increases to 1/3.then t1 and t2 respectively

Answers

Answered by shreyasharma39

2

apply 2 equations,
1/6 = T1 - T2/ T1
1/3= T1 - (T2-62)/T1
Solve these two to get your answer

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