Question

A carnot engine takes 3× 10⁶ cal of heat from a reservoir at 627°C and gives it to a sink at 27°C . The work done by the engine is . [AIEEE 2003] ​

Answer 1

Explanation:-. Given , T₁= 627°C = 627 + 273= 900k

Q₁ = 3×10⁶Cal

T₂ = 27+ 273 = 300K

Now , Q ₁/T₁= Q ₂ /T₂

⟹ Q₂ = T₂/T₁ × Q ₁

⟹ Q₂ = 300/900 × 3× 10⁶

⟹ Q₂ = 1× 10⁶ Cal

Work done by the engine is 1× 10⁶ cal

Answer 2

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