A Carnot engine takes in 1000 k cal of heat from a reservoir at627°c and exhaust heat to sink at 27°c.what useful work done/cycle
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Efficiency is given by the relation:
∩=W/Q1=Q1-Q2/Q1=T1-T2/T1
Q1=1000K cal=10^6 cal
T1=627+273=900K
T2=27+273=300K
∩=900-300/900=66.67%
Work done by the engine is given by∩Q1
W=∩Q1
66.67×10^6×4.2×10^7
=2.8×10^13 ergs
∩=W/Q1=Q1-Q2/Q1=T1-T2/T1
Q1=1000K cal=10^6 cal
T1=627+273=900K
T2=27+273=300K
∩=900-300/900=66.67%
Work done by the engine is given by∩Q1
W=∩Q1
66.67×10^6×4.2×10^7
=2.8×10^13 ergs
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