Question

A carnot engine , whose efficiency is 40% takes in heat from a source maintained at a temprature of 500k . it is desired to have an engine of efficiency 60% then , the intake temprature for the same exhaust (sink) temprature must be [AIEEE 2012] ​

Answer 1

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Answer 2

Explanation:- Given efficiency 40% = 0.4 Tsource = 500K

η = 1- Tsink/Tsource

0.4 = 1- Tsink /Tsource

⟹ Tsink = (1-0.4)× Tsource

⟹Tsink = 0.6× 500k = 300K

Thus , η'= 1-300k/T'source

0.6 = 1- 300K/T'souce

⟹ T'source = 300K /0.4 = 750K answer