A carnot engine whose source is at 1000k takes 800cal of heat and rejects 600cal to the sink determine temperature of the sink
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Answer:
750K
Explanation:
T(source)= 1000K
Q1=800cal
Q2=600cal
T(sink) Q2
--------- = -----
T(source) Q1
i.e, T(sink) = (600/800)× 1000
= (6/8)×1000
= 0.75 × 1000
= 750K
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