Question

A carnot engine working between 400k and 800k has a work output of 1200j per cycle . What is the amount of heat energy supplied to the engine from source per cycle

Answer 1

T2 = 400 K

T1 = 800 K

η = 1-T2/T1

η = 1-400/800

η= 1/2

Q = W/η

Q = 1200/0.5

Q = 2400 J

Answer 2

Answer:

2400J

Explanation:

$\frac{400}{800}=1-\frac{W}{Q}$

$\frac{1}{2}=1-\frac{W}{Q}$

$\frac{W}{Q}=1-\frac{1}{2}$

$\frac{W}{Q}=\frac{1}{2}$

$Q=2W$$=2(1200)=2400J$

Therefore, Q=2400J

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