Question

A Carnot engine working between an unknown temperature T and ice point gives an efficiency of 0.68. Deduce the value of T

Answer 1

Efficiency=[1-(lower temp./higher temp)]
0.68=1-(273.15/higher temp)
0.32=273.15/higher temp
Higher temp=853.59K

Answer 2

The value of T is 853.59 K.

Explanation:

Ice point means the temperature is 273.15 K. It is mentioned that a carnot engine working between an unknown temperature T and ice point gives an efficiency of 0.68. The formula of the efficiency of carnot engine is given by :

$\eta=1-\dfrac{T_2}{T_1}$

Here, T₂ = 273.15 K

and T₁ = T

$\eta=1-\dfrac{T_2}{T}\\\\T=\dfrac{T_2}{1-\eta}\\\\T=\dfrac{273.15}{1-0.68}\\\\T=853.59\ K$

So, the value of T is 853.59 K.

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Carnot engine

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