Question

a carnot engine works aa a refrigerator between 250k and 300k . it it receives 750cal of heat from the reservoir at the lower temperature. calculate the amount of heat rejected at the higher temperature ?​

Answer 1

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Answer 2

Answer:

Explanation:

Q2/Q1 = T2/T1 = 250/300 = 5/6

Q2 = 500  cal  

Q1 = 600 cal

W = Q1-Q2 = 100 cal