A Carnot's engine has an efficiency of 60% %
with its sink at 270 °C. Calculate the
temperature of the Source.
Answers
Answered by
0
Explanation:
Correct option is B)
The efficiency of the cycle is given as η=1−
T
1
T
2
. Here T
1
is the temperature of the source and T
2
is the temperature of the sink. The temperature of the sink is given as 27
o
C=300K. Thus we get 0.5=1−
T
1
300
or
T
1
=600K=327
o
C
Answered by
0
Answer:
327 degree Celsius
Explanation :
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