Physics, asked by bhavanalotanpatil, 20 days ago

A Carnot's engine has an efficiency of 60% %
with its sink at 270 °C. Calculate the
temperature of the Source.​

Answers

Answered by srinivasaraomoyili
0

Explanation:

Correct option is B)

The efficiency of the cycle is given as η=1−

T

1

T

2

. Here T

1

is the temperature of the source and T

2

is the temperature of the sink. The temperature of the sink is given as 27

o

C=300K. Thus we get 0.5=1−

T

1

300

or

T

1

=600K=327

o

C

Answered by Jeetesh2903
0

Answer:

327 degree Celsius

Explanation :

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