Physics, asked by suswetamondal08061, 8 months ago

A Carnot's heat engine working between 150 K and 300 K has a work
output of 500 J per cycle. Calculate the heat supplied to the engine from the
source.​

Answers

Answered by Anonymous
30

\huge\underline{\underline{\bf \orange{Question-}}}

A Carnot's heat engine working between 150 K and 300 K has a work output of 500 J per cycle. Calculate the heat supplied to the engine from the source.

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Temperature source = 150K
  • Temperature sink = 300K
  • Work output (W) = 500J

\large\underline{\underline{\sf To\:Find:}}

  • Heat supplied ( Q )

\large{\boxed{\bf \blue{\dfrac{W}{Q}=\left(1-\dfrac{T_1}{T_2}\right)} }}

\implies{\sf \dfrac{500}{Q}=\left(1-\dfrac{150}{300}\right) }

\implies{\sf  \dfrac{500}{Q}=\dfrac{300-150}{300}}

\implies{\sf  \dfrac{500}{Q}=\dfrac{150}{300}}

\implies{\sf \dfrac{500}{Q}=\dfrac{1}{2}}

\implies{\sf Q = 500 × 2}

\implies{\bf \red{Heat \: Supplied (Q)=1000J} }

\huge\underline{\underline{\bf \orange{Answer -}}}

Heat supplied to the engine from the source is {\bf \red{1000J}}.

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