Question

A carnot's heat engine working between 300K and 600K has work output of 800J per cycle. Calculate the heat supplied to the engine from the source.​

Answer 1

Efficiency is given by (1 - T1/T2) and also by (Work done)/(heat supplied) and we are given with T1, T2 and work done.

Thus on equating both formula we will get the value of heat supplied.

Hence your answer is 1600 J

1 - T1/T2 = W/Q1

1 - 300/600 = 800/Q1

1 - 0.5 = 800/Q1

0.5 = 800/Q1

Q1 = 800/0.5

Q1 = 1600 J

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