Question

A carpenter makes a circular design. He
equilateral AABC in the circle,
inscribes an
5. V
such that all the three vertices of AABC lies
on the circle as shown.
Point O is centre of circle.
Radius OA=
OB = OC = 21 cm
(a) Area of circular design is
(in) 1384 cm
(1) 1386 cm
(ii) 1380 cm
(iv) 1381 cm​

Answer 1

Answer:

1386cm²

Step-by-step explanation:

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Answer 2

Given: An equilateral triangle ABC is inscribed in the circular design.

Point O is centre of circle.

Radius OA = OB = OC = 21 cm.

To find: Area of circular design

Solution: The radius of the circle is given as 21 cm.

We know the area of a circle is given bby the formula = $\pi$r² (where r is the radius of the circle).

As such, here r = 21 cm.

Hence, the area of the circular design

= $\pi$ × (21)²

= 22/7 × 21 × 21

= 22 × 21 × 3

= 1386 cm²

Answer: Option 1386 cm²